Functional Maths and Football
Answers
1. (a) Brazil (b) 6 (c) England
2. (a) 22 (b) 27 (c) 27 (d) 15 (e) 27
3. (a) 4/6 = 2/3 (b) 2 (c) 2/20= 1/10 (d) 42
4. (a) 21ºC (b) 8ºC 3. (a) 4/6 = 2/3 (b) 2 (c) 2/20= 1/10 (d) 42
(c) The temperature increases until 14:00 then starts to decrease until the end of the day.
Functional Maths
Need help with Mr Walker's Gas Bill? Check out this YouTube video.
Digging the hole!
Start from the basis that we know
5 x R = 100 cu. feet and 6 x C = 100 cu. feet
So, R = 20 cu. feet per hour and C = 100/6 cu. feet per hour
So,
time for two = 100 / (R + C) = 2.73 hours = 2 hours 44 minutes
You end up with ....
What a beautiful baby!!
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All these years later and I have the same!! |
Hence on 24th Dec. 2012 I will be 54
54 x 365 = 19710 days
between 1958 and 2012 there are 13 leap years = 13 extra days
19710 + 13 = 19723 days
December has 31 days hence 6 days left in 1958
Total days = 19723 + 6 = 19729 days
Christmas Presents
32 | 16 | 8 | 4 | 2 | 1 | |||||
January 1st, 2011 | 0 | 1 | 0 | 1 | 1 | 1 | = | 23 | ||
January 10th, 2011 | 1 | 0 | 0 | 1 | 1 | 1 | = | 39 | ||
January 11th, 2011 | 1 | 1 | 0 | 1 | 1 | 1 | = | 55 | ||
October 1st, 2011 | 0 | 1 | 1 | 0 | 1 | 1 | = | 27 | ||
October 10th, 2011 | 1 | 0 | 1 | 0 | 1 | 1 | = | 43 | ||
October 11th, 2011 | 1 | 1 | 1 | 0 | 1 | 1 | = | 59 | ||
November 1st, 2011 | 0 | 1 | 1 | 1 | 1 | 1 | = | 31 | ||
November 10th, 2011 | 1 | 0 | 1 | 1 | 1 | 1 | = | 47 | ||
November 11th, 2011 | 1 | 1 | 1 | 1 | 1 | 1 | = | 63 |
If you count the partridge and the pear tree as seperate items the total number of presents is 376.
Binary Dates